Base | Representation |
---|---|
bin | 11000100101101100… |
… | …10110100101000111 |
3 | 1021002000021101201120 |
4 | 30102312112211013 |
5 | 204013442440124 |
6 | 10021534125023 |
7 | 645064560513 |
oct | 142266264507 |
9 | 37060241646 |
10 | 13201140039 |
11 | 566477699a |
12 | 2685050773 |
13 | 1324c67b89 |
14 | 8d3367143 |
15 | 523e33d79 |
hex | 312d96947 |
13201140039 has 4 divisors (see below), whose sum is σ = 17601520056. Its totient is φ = 8800760024.
The previous prime is 13201140031. The next prime is 13201140041. The reversal of 13201140039 is 93004110231.
13201140039 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 93004110231 = 3 ⋅31001370077.
It is a cyclic number.
It is not a de Polignac number, because 13201140039 - 23 = 13201140031 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13201140031) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2200190004 + ... + 2200190009.
It is an arithmetic number, because the mean of its divisors is an integer number (4400380014).
Almost surely, 213201140039 is an apocalyptic number.
13201140039 is a deficient number, since it is larger than the sum of its proper divisors (4400380017).
13201140039 is an equidigital number, since it uses as much as digits as its factorization.
13201140039 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4400380016.
The product of its (nonzero) digits is 648, while the sum is 24.
The spelling of 13201140039 in words is "thirteen billion, two hundred one million, one hundred forty thousand, thirty-nine".
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