Base | Representation |
---|---|
bin | 11000100101101100… |
… | …10110110100100110 |
3 | 1021002000021110002021 |
4 | 30102312112310212 |
5 | 204013443003110 |
6 | 10021534133354 |
7 | 645064563430 |
oct | 142266266446 |
9 | 37060243067 |
10 | 13201141030 |
11 | 5664777710 |
12 | 268505125a |
13 | 1324c6846c |
14 | 8d3367650 |
15 | 523e342da |
hex | 312d96d26 |
13201141030 has 64 divisors (see below), whose sum is σ = 29642899968. Its totient is φ = 4112213760.
The previous prime is 13201141021. The next prime is 13201141097. The reversal of 13201141030 is 3014110231.
13201141030 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a junction number, because it is equal to n+sod(n) for n = 13201140995 and 13201141013.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1653829 + ... + 1661791.
It is an arithmetic number, because the mean of its divisors is an integer number (463170312).
Almost surely, 213201141030 is an apocalyptic number.
13201141030 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
13201141030 is an abundant number, since it is smaller than the sum of its proper divisors (16441758938).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13201141030 is a wasteful number, since it uses less digits than its factorization.
13201141030 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 10141.
The product of its (nonzero) digits is 72, while the sum is 16.
Adding to 13201141030 its reverse (3014110231), we get a palindrome (16215251261).
The spelling of 13201141030 in words is "thirteen billion, two hundred one million, one hundred forty-one thousand, thirty".
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