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13201155042293 is a prime number
BaseRepresentation
bin1100000000011010001000…
…1010000010101111110101
31201202000111012012102221002
43000012202022002233311
53212241431142323133
644024305451133045
72531515633266551
oct300064212025765
951660435172832
1013201155042293
11422a63a9602a9
121592580144185
13749b2c38a76a
14338d21692861
1517d5d4215ce8
hexc01a2282bf5

13201155042293 has 2 divisors, whose sum is σ = 13201155042294. Its totient is φ = 13201155042292.

The previous prime is 13201155042253. The next prime is 13201155042311. The reversal of 13201155042293 is 39224055110231.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8320559473444 + 4880595568849 = 2884538^2 + 2209207^2 .

It is a cyclic number.

It is not a de Polignac number, because 13201155042293 - 214 = 13201155025909 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13201155042223) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6600577521146 + 6600577521147.

It is an arithmetic number, because the mean of its divisors is an integer number (6600577521147).

Almost surely, 213201155042293 is an apocalyptic number.

It is an amenable number.

13201155042293 is a deficient number, since it is larger than the sum of its proper divisors (1).

13201155042293 is an equidigital number, since it uses as much as digits as its factorization.

13201155042293 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 64800, while the sum is 38.

The spelling of 13201155042293 in words is "thirteen trillion, two hundred one billion, one hundred fifty-five million, forty-two thousand, two hundred ninety-three".