Base | Representation |
---|---|
bin | 1100000000011010010110… |
… | …0111100110010111010111 |
3 | 1201202000122020111012022121 |
4 | 3000012211213212113113 |
5 | 3212242041024401012 |
6 | 44024315324040411 |
7 | 2531520240045301 |
oct | 300064547462727 |
9 | 51660566435277 |
10 | 13201213122007 |
11 | 422a66a71a469 |
12 | 1592597693107 |
13 | 749b3b414661 |
14 | 338d29290971 |
15 | 17d5d9389a07 |
hex | c01a59e65d7 |
13201213122007 has 2 divisors, whose sum is σ = 13201213122008. Its totient is φ = 13201213122006.
The previous prime is 13201213121959. The next prime is 13201213122029. The reversal of 13201213122007 is 70022131210231.
13201213122007 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is an emirp because it is prime and its reverse (70022131210231) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13201213122007 - 223 = 13201204733399 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13201213122037) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6600606561003 + 6600606561004.
It is an arithmetic number, because the mean of its divisors is an integer number (6600606561004).
Almost surely, 213201213122007 is an apocalyptic number.
13201213122007 is a deficient number, since it is larger than the sum of its proper divisors (1).
13201213122007 is an equidigital number, since it uses as much as digits as its factorization.
13201213122007 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1008, while the sum is 25.
Adding to 13201213122007 its reverse (70022131210231), we get a palindrome (83223344332238).
The spelling of 13201213122007 in words is "thirteen trillion, two hundred one billion, two hundred thirteen million, one hundred twenty-two thousand, seven".
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