Base | Representation |
---|---|
bin | 1100000000011010011011… |
… | …1000110100101011110111 |
3 | 1201202000200201112221220001 |
4 | 3000012212320310223313 |
5 | 3212242112002224302 |
6 | 44024321404252131 |
7 | 2531520616036111 |
oct | 300064670645367 |
9 | 51660621487801 |
10 | 13201234414327 |
11 | 422a680742723 |
12 | 15925a2841047 |
13 | 749b4295b06b |
14 | 338d2c0343b1 |
15 | 17d5db193787 |
hex | c01a6e34af7 |
13201234414327 has 2 divisors, whose sum is σ = 13201234414328. Its totient is φ = 13201234414326.
The previous prime is 13201234414309. The next prime is 13201234414343. The reversal of 13201234414327 is 72341443210231.
It is a happy number.
13201234414327 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13201234414327 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13201234414307) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6600617207163 + 6600617207164.
It is an arithmetic number, because the mean of its divisors is an integer number (6600617207164).
Almost surely, 213201234414327 is an apocalyptic number.
13201234414327 is a deficient number, since it is larger than the sum of its proper divisors (1).
13201234414327 is an equidigital number, since it uses as much as digits as its factorization.
13201234414327 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 96768, while the sum is 37.
Adding to 13201234414327 its reverse (72341443210231), we get a palindrome (85542677624558).
The spelling of 13201234414327 in words is "thirteen trillion, two hundred one billion, two hundred thirty-four million, four hundred fourteen thousand, three hundred twenty-seven".
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