Base | Representation |
---|---|
bin | 11110000001000010001010… |
… | …100111110000110011110000 |
3 | 122022102021011221211110200011 |
4 | 132001002022213300303300 |
5 | 114300342434231123300 |
6 | 1144433402233504304 |
7 | 36543404224501405 |
oct | 3601021247606360 |
9 | 568367157743604 |
10 | 132012440489200 |
11 | 3907718610a747 |
12 | 12980a8b272094 |
13 | 58879482caa6b |
14 | 2485616d702ac |
15 | 103de2e806eba |
hex | 78108a9f0cf0 |
132012440489200 has 120 divisors (see below), whose sum is σ = 318273703398000. Its totient is φ = 52619569121280.
The previous prime is 132012440489147. The next prime is 132012440489201. The reversal of 132012440489200 is 2984044210231.
It is a Harshad number since it is a multiple of its sum of digits (40).
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (132012440489201) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 1324192956 + ... + 1324292644.
It is an arithmetic number, because the mean of its divisors is an integer number (2652280861650).
Almost surely, 2132012440489200 is an apocalyptic number.
132012440489200 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 132012440489200, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (159136851699000).
132012440489200 is an abundant number, since it is smaller than the sum of its proper divisors (186261262908800).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
132012440489200 is a wasteful number, since it uses less digits than its factorization.
132012440489200 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 111299 (or 111288 counting only the distinct ones).
The product of its (nonzero) digits is 110592, while the sum is 40.
Adding to 132012440489200 its reverse (2984044210231), we get a palindrome (134996484699431).
The spelling of 132012440489200 in words is "one hundred thirty-two trillion, twelve billion, four hundred forty million, four hundred eighty-nine thousand, two hundred".
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