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132013132441 is a prime number
BaseRepresentation
bin111101011110010011…
…0001000101010011001
3110121202012222222011121
41322330212020222121
54130330330214231
6140351311325241
712352260053101
oct1727446105231
9417665888147
10132013132441
1150a93a76353
1221702b20821
13c5aac99468
1465649c2201
15367996c311
hex1ebc988a99

132013132441 has 2 divisors, whose sum is σ = 132013132442. Its totient is φ = 132013132440.

The previous prime is 132013132439. The next prime is 132013132523. The reversal of 132013132441 is 144231310231.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 128865922441 + 3147210000 = 358979^2 + 56100^2 .

It is a cyclic number.

It is not a de Polignac number, because 132013132441 - 21 = 132013132439 is a prime.

Together with 132013132439, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (132013130441) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66006566220 + 66006566221.

It is an arithmetic number, because the mean of its divisors is an integer number (66006566221).

Almost surely, 2132013132441 is an apocalyptic number.

It is an amenable number.

132013132441 is a deficient number, since it is larger than the sum of its proper divisors (1).

132013132441 is an equidigital number, since it uses as much as digits as its factorization.

132013132441 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 132013132441 its reverse (144231310231), we get a palindrome (276244442672).

The spelling of 132013132441 in words is "one hundred thirty-two billion, thirteen million, one hundred thirty-two thousand, four hundred forty-one".