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132013211013119 is a prime number
BaseRepresentation
bin11110000001000010111000…
…100011000100111111111111
3122022102100011122201010210002
4132001002320203010333333
5114300401024004404434
61144434010520504515
736543432302031002
oct3601027043047777
9568370148633702
10132013211013119
1139077541048777
121298106531b13b
135887a3bb30287
14248568b425539
15103de772aa57e
hex7810b88c4fff

132013211013119 has 2 divisors, whose sum is σ = 132013211013120. Its totient is φ = 132013211013118.

The previous prime is 132013211013083. The next prime is 132013211013139. The reversal of 132013211013119 is 911310112310231.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-132013211013119 is a prime.

It is a super-2 number, since 2×1320132110131192 (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 132013211013091 and 132013211013100.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (132013211013139) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66006605506559 + 66006605506560.

It is an arithmetic number, because the mean of its divisors is an integer number (66006605506560).

Almost surely, 2132013211013119 is an apocalyptic number.

132013211013119 is a deficient number, since it is larger than the sum of its proper divisors (1).

132013211013119 is an equidigital number, since it uses as much as digits as its factorization.

132013211013119 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 972, while the sum is 29.

The spelling of 132013211013119 in words is "one hundred thirty-two trillion, thirteen billion, two hundred eleven million, thirteen thousand, one hundred nineteen".