13201333110023 has 2 divisors, whose sum is σ = 13201333110024. Its totient is φ = 13201333110022.

The previous prime is 13201333109999. The next prime is 13201333110059. The reversal of 13201333110023 is 32001133310231.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13201333110023 is a prime.

It is a super-4 number, since 4×13201333110023⁴ (a number of 54 digits) contains 4444 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13201333100023) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6600666555011 + 6600666555012.

It is an arithmetic number, because the mean of its divisors is an integer number (6600666555012).

Almost surely, 2^{13201333110023} is an apocalyptic number.

13201333110023 is a deficient number, since it is larger than the sum of its proper divisors (1).

13201333110023 is an equidigital number, since it uses as much as digits as its factorization.

13201333110023 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 972, while the sum is 23.

Adding to 13201333110023 its reverse (32001133310231), we get a palindrome (45202466420254).

The spelling of 13201333110023 in words is "thirteen trillion, two hundred one billion, three hundred thirty-three million, one hundred ten thousand, twenty-three".