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13201500510257 is a prime number
BaseRepresentation
bin1100000000011011011010…
…1111111001100000110001
31201202001101021021000212212
43000012312233321200301
53212243133112312012
644024404031501505
72531530326600023
oct300066657714061
951661337230785
1013201500510257
11422a7a796a514
121592657987895
13749b85b17b87
14338d55500013
1517d604706b22
hexc01b6bf9831

13201500510257 has 2 divisors, whose sum is σ = 13201500510258. Its totient is φ = 13201500510256.

The previous prime is 13201500510229. The next prime is 13201500510259. The reversal of 13201500510257 is 75201500510231.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12254088341056 + 947412169201 = 3500584^2 + 973351^2 .

It is a cyclic number.

It is not a de Polignac number, because 13201500510257 - 28 = 13201500510001 is a prime.

Together with 13201500510259, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (13201500510259) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6600750255128 + 6600750255129.

It is an arithmetic number, because the mean of its divisors is an integer number (6600750255129).

Almost surely, 213201500510257 is an apocalyptic number.

It is an amenable number.

13201500510257 is a deficient number, since it is larger than the sum of its proper divisors (1).

13201500510257 is an equidigital number, since it uses as much as digits as its factorization.

13201500510257 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 10500, while the sum is 32.

The spelling of 13201500510257 in words is "thirteen trillion, two hundred one billion, five hundred million, five hundred ten thousand, two hundred fifty-seven".