1320150219343 has 2 divisors, whose sum is σ = 1320150219344. Its totient is φ = 1320150219342.

The previous prime is 1320150219337. The next prime is 1320150219379. The reversal of 1320150219343 is 3439120510231.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1320150219343 is a prime.

It is a super-2 number, since 2×1320150219343² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1320150219299 and 1320150219308.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1320150219943) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 660075109671 + 660075109672.

It is an arithmetic number, because the mean of its divisors is an integer number (660075109672).

Almost surely, 2^{1320150219343} is an apocalyptic number.

1320150219343 is a deficient number, since it is larger than the sum of its proper divisors (1).

1320150219343 is an equidigital number, since it uses as much as digits as its factorization.

1320150219343 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 19440, while the sum is 34.

Adding to 1320150219343 its reverse (3439120510231), we get a palindrome (4759270729574).

The spelling of 1320150219343 in words is "one trillion, three hundred twenty billion, one hundred fifty million, two hundred nineteen thousand, three hundred forty-three".