Base | Representation |
---|---|
bin | 1100000000011101010101… |
… | …0011110100010010110000 |
3 | 1201202002201000001112100120 |
4 | 3000013111103310102300 |
5 | 3212300210342230134 |
6 | 44024530545250240 |
7 | 2531546124003240 |
oct | 300072523642260 |
9 | 51662630045316 |
10 | 13202013242544 |
11 | 422aa40332905 |
12 | 159277b633980 |
13 | 749c3810a369 |
14 | 338da364bb20 |
15 | 17d634737649 |
hex | c01d54f44b0 |
13202013242544 has 80 divisors (see below), whose sum is σ = 38981550854400. Its totient is φ = 3771599420160.
The previous prime is 13202013242543. The next prime is 13202013242567. The reversal of 13202013242544 is 44524231020231.
It is a happy number.
It is not an unprimeable number, because it can be changed into a prime (13202013242543) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1039879 + ... + 5242649.
It is an arithmetic number, because the mean of its divisors is an integer number (487269385680).
Almost surely, 213202013242544 is an apocalyptic number.
13202013242544 is a gapful number since it is divisible by the number (14) formed by its first and last digit.
It is an amenable number.
13202013242544 is an abundant number, since it is smaller than the sum of its proper divisors (25779537611856).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13202013242544 is a wasteful number, since it uses less digits than its factorization.
13202013242544 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4212138 (or 4212132 counting only the distinct ones).
The product of its (nonzero) digits is 46080, while the sum is 33.
Adding to 13202013242544 its reverse (44524231020231), we get a palindrome (57726244262775).
The spelling of 13202013242544 in words is "thirteen trillion, two hundred two billion, thirteen million, two hundred forty-two thousand, five hundred forty-four".
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