Search a number
-
+
132020153540999 is a prime number
BaseRepresentation
bin11110000001001001010110…
…010110101110000110000111
3122022110000002111022002122022
4132001021112112232012013
5114301004233301302444
61144441115443153355
736544066322402033
oct3601112626560607
9568400074262568
10132020153540999
113907a483a08719
121298248237585b
1358885a7262a39
142485b494a11c3
15103e231a209ee
hex7812565ae187

132020153540999 has 2 divisors, whose sum is σ = 132020153541000. Its totient is φ = 132020153540998.

The previous prime is 132020153540981. The next prime is 132020153541019. The reversal of 132020153540999 is 999045351020231.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 132020153540999 - 224 = 132020136763783 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 132020153540999.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (132020153540959) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66010076770499 + 66010076770500.

It is an arithmetic number, because the mean of its divisors is an integer number (66010076770500).

Almost surely, 2132020153540999 is an apocalyptic number.

132020153540999 is a deficient number, since it is larger than the sum of its proper divisors (1).

132020153540999 is an equidigital number, since it uses as much as digits as its factorization.

132020153540999 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2624400, while the sum is 53.

The spelling of 132020153540999 in words is "one hundred thirty-two trillion, twenty billion, one hundred fifty-three million, five hundred forty thousand, nine hundred ninety-nine".