Base | Representation |
---|---|
bin | 111101011110100010… |
… | …0100101000111110101 |
3 | 110121202210000102220012 |
4 | 1322331010211013311 |
5 | 4130334401111313 |
6 | 140352154350005 |
7 | 12352414643024 |
oct | 1727504450765 |
9 | 417683012805 |
10 | 132021113333 |
11 | 50a9852752a |
12 | 2170572b305 |
13 | c5ac831c95 |
14 | 6565a9c8bb |
15 | 367a4e6da8 |
hex | 1ebd1251f5 |
132021113333 has 2 divisors, whose sum is σ = 132021113334. Its totient is φ = 132021113332.
The previous prime is 132021113311. The next prime is 132021113377. The reversal of 132021113333 is 333311120231.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 70329979204 + 61691134129 = 265198^2 + 248377^2 .
It is a cyclic number.
It is not a de Polignac number, because 132021113333 - 210 = 132021112309 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 132021113299 and 132021113308.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (132021113303) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66010556666 + 66010556667.
It is an arithmetic number, because the mean of its divisors is an integer number (66010556667).
Almost surely, 2132021113333 is an apocalyptic number.
It is an amenable number.
132021113333 is a deficient number, since it is larger than the sum of its proper divisors (1).
132021113333 is an equidigital number, since it uses as much as digits as its factorization.
132021113333 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 972, while the sum is 23.
Adding to 132021113333 its reverse (333311120231), we get a palindrome (465332233564).
The spelling of 132021113333 in words is "one hundred thirty-two billion, twenty-one million, one hundred thirteen thousand, three hundred thirty-three".
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