1320211200053 has 2 divisors, whose sum is σ = 1320211200054. Its totient is φ = 1320211200052.

The previous prime is 1320211200013. The next prime is 1320211200073. The reversal of 1320211200053 is 3500021120231.

It is an a-pointer prime, because the next prime (1320211200073) can be obtained adding 1320211200053 to its sum of digits (20).

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 966206429764 + 354004770289 = 982958^2 + 594983^2 .

It is a cyclic number.

It is not a de Polignac number, because 1320211200053 - 2¹⁰ = 1320211199029 is a prime.

It is a super-2 number, since 2×1320211200053² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1320211199998 and 1320211200034.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1320211200013) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 660105600026 + 660105600027.

It is an arithmetic number, because the mean of its divisors is an integer number (660105600027).

Almost surely, 2^{1320211200053} is an apocalyptic number.

It is an amenable number.

1320211200053 is a deficient number, since it is larger than the sum of its proper divisors (1).

1320211200053 is an equidigital number, since it uses as much as digits as its factorization.

1320211200053 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 360, while the sum is 20.

Adding to 1320211200053 its reverse (3500021120231), we get a palindrome (4820232320284).

The spelling of 1320211200053 in words is "one trillion, three hundred twenty billion, two hundred eleven million, two hundred thousand, fifty-three".