1320211200431 has 2 divisors, whose sum is σ = 1320211200432. Its totient is φ = 1320211200430.

The previous prime is 1320211200391. The next prime is 1320211200433. The reversal of 1320211200431 is 1340021120231.

It is a strong prime.

It is an emirp because it is prime and its reverse (1340021120231) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1320211200431 is a prime.

It is a super-2 number, since 2×1320211200431² (a number of 25 digits) contains 22 as substring.

Together with 1320211200433, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1320211200433) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 660105600215 + 660105600216.

It is an arithmetic number, because the mean of its divisors is an integer number (660105600216).

Almost surely, 2^{1320211200431} is an apocalyptic number.

1320211200431 is a deficient number, since it is larger than the sum of its proper divisors (1).

1320211200431 is an equidigital number, since it uses as much as digits as its factorization.

1320211200431 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 288, while the sum is 20.

Adding to 1320211200431 its reverse (1340021120231), we get a palindrome (2660232320662).

The spelling of 1320211200431 in words is "one trillion, three hundred twenty billion, two hundred eleven million, two hundred thousand, four hundred thirty-one".