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13202211000103 is a prime number
BaseRepresentation
bin1100000000011110000100…
…0110001100111100100111
31201202010012210011122201121
43000013201012030330213
53212301112004000403
644025002332034411
72531554044631006
oct300074106147447
951663183148647
1013202211000103
114230031a24004
121592815902a07
13749c6a08aa78
14338dc1a08c3d
1517d646c9c3bd
hexc01e118cf27

13202211000103 has 2 divisors, whose sum is σ = 13202211000104. Its totient is φ = 13202211000102.

The previous prime is 13202211000101. The next prime is 13202211000109. The reversal of 13202211000103 is 30100011220231.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 13202211000103 - 21 = 13202211000101 is a prime.

Together with 13202211000101, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13202211000101) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6601105500051 + 6601105500052.

It is an arithmetic number, because the mean of its divisors is an integer number (6601105500052).

Almost surely, 213202211000103 is an apocalyptic number.

13202211000103 is a deficient number, since it is larger than the sum of its proper divisors (1).

13202211000103 is an equidigital number, since it uses as much as digits as its factorization.

13202211000103 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 72, while the sum is 16.

Adding to 13202211000103 its reverse (30100011220231), we get a palindrome (43302222220334).

The spelling of 13202211000103 in words is "thirteen trillion, two hundred two billion, two hundred eleven million, one hundred three", and thus it is an aban number.