Base | Representation |
---|---|
bin | 10011001101100011010… |
… | …100001010111101011011 |
3 | 11200012201111002102220012 |
4 | 103031203110022331123 |
5 | 133112303111121102 |
6 | 2450300133552135 |
7 | 164245211655113 |
oct | 23154324127533 |
9 | 4605644072805 |
10 | 1320221192027 |
11 | 4699a2499041 |
12 | 193a4b4a564b |
13 | 9765b56921a |
14 | 47c82dac043 |
15 | 2451e2d4752 |
hex | 1336350af5b |
1320221192027 has 2 divisors, whose sum is σ = 1320221192028. Its totient is φ = 1320221192026.
The previous prime is 1320221192011. The next prime is 1320221192029. The reversal of 1320221192027 is 7202911220231.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1320221192027 - 24 = 1320221192011 is a prime.
Together with 1320221192029, it forms a pair of twin primes.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 1320221191984 and 1320221192002.
It is not a weakly prime, because it can be changed into another prime (1320221192029) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 660110596013 + 660110596014.
It is an arithmetic number, because the mean of its divisors is an integer number (660110596014).
Almost surely, 21320221192027 is an apocalyptic number.
1320221192027 is a deficient number, since it is larger than the sum of its proper divisors (1).
1320221192027 is an equidigital number, since it uses as much as digits as its factorization.
1320221192027 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6048, while the sum is 32.
The spelling of 1320221192027 in words is "one trillion, three hundred twenty billion, two hundred twenty-one million, one hundred ninety-two thousand, twenty-seven".
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