Base | Representation |
---|---|
bin | 1100000000011110000110… |
… | …1110000000010101011000 |
3 | 1201202010020111210202121122 |
4 | 3000013201232000111120 |
5 | 3212301122141343300 |
6 | 44025003343424412 |
7 | 2531554232416061 |
oct | 300074156002530 |
9 | 51663214722548 |
10 | 13202221434200 |
11 | 4230037900327 |
12 | 15928192b5108 |
13 | 749c6c2a20a6 |
14 | 338dc3163568 |
15 | 17d647b5dc85 |
hex | c01e1b80558 |
13202221434200 has 48 divisors (see below), whose sum is σ = 30726907957680. Its totient is φ = 5275427391360.
The previous prime is 13202221434187. The next prime is 13202221434239. The reversal of 13202221434200 is 243412220231.
It is a self number, because there is not a number n which added to its sum of digits gives 13202221434200.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 33938507 + ... + 34325306.
It is an arithmetic number, because the mean of its divisors is an integer number (640143915785).
Almost surely, 213202221434200 is an apocalyptic number.
13202221434200 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
13202221434200 is an abundant number, since it is smaller than the sum of its proper divisors (17524686523480).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13202221434200 is a wasteful number, since it uses less digits than its factorization.
13202221434200 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 68264796 (or 68264787 counting only the distinct ones).
The product of its (nonzero) digits is 4608, while the sum is 26.
Adding to 13202221434200 its reverse (243412220231), we get a palindrome (13445633654431).
The spelling of 13202221434200 in words is "thirteen trillion, two hundred two billion, two hundred twenty-one million, four hundred thirty-four thousand, two hundred".
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