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132024115208749 is a prime number
BaseRepresentation
bin11110000001001101000010…
…011111010010001000101101
3122022110101022120212200010111
4132001031002133102020231
5114301040341443134444
61144443012523340021
736544266436124551
oct3601150237221055
9568411276780114
10132024115208749
11390811271a02a5
12129831a9081611
135888a88c52a3a
1424860036b7861
15103e3b4723234
hex7813427d222d

132024115208749 has 2 divisors, whose sum is σ = 132024115208750. Its totient is φ = 132024115208748.

The previous prime is 132024115208747. The next prime is 132024115208753. The reversal of 132024115208749 is 947802511420231.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 88178767026025 + 43845348182724 = 9390355^2 + 6621582^2 .

It is a cyclic number.

It is not a de Polignac number, because 132024115208749 - 21 = 132024115208747 is a prime.

It is a super-2 number, since 2×1320241152087492 (a number of 29 digits) contains 22 as substring.

Together with 132024115208747, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (132024115208747) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66012057604374 + 66012057604375.

It is an arithmetic number, because the mean of its divisors is an integer number (66012057604375).

Almost surely, 2132024115208749 is an apocalyptic number.

It is an amenable number.

132024115208749 is a deficient number, since it is larger than the sum of its proper divisors (1).

132024115208749 is an equidigital number, since it uses as much as digits as its factorization.

132024115208749 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 967680, while the sum is 49.

The spelling of 132024115208749 in words is "one hundred thirty-two trillion, twenty-four billion, one hundred fifteen million, two hundred eight thousand, seven hundred forty-nine".