13202414310013 has 2 divisors, whose sum is σ = 13202414310014. Its totient is φ = 13202414310012.

The previous prime is 13202414309993. The next prime is 13202414310049. The reversal of 13202414310013 is 31001341420231.

13202414310013 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 6745723146009 + 6456691164004 = 2597253^2 + 2541002^2 .

It is a cyclic number.

It is not a de Polignac number, because 13202414310013 - 2³⁷ = 13064975356541 is a prime.

It is a super-2 number, since 2×13202414310013² (a number of 27 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 13202414310013.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13202414313013) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6601207155006 + 6601207155007.

It is an arithmetic number, because the mean of its divisors is an integer number (6601207155007).

Almost surely, 2^{13202414310013} is an apocalyptic number.

It is an amenable number.

13202414310013 is a deficient number, since it is larger than the sum of its proper divisors (1).

13202414310013 is an equidigital number, since it uses as much as digits as its factorization.

13202414310013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 13202414310013 its reverse (31001341420231), we get a palindrome (44203755730244).

The spelling of 13202414310013 in words is "thirteen trillion, two hundred two billion, four hundred fourteen million, three hundred ten thousand, thirteen".