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1320302231341 is a prime number
BaseRepresentation
bin10011001101101000001…
…001010011111100101101
311200012221010120122221021
4103031220021103330231
5133112434332400331
62450312150534141
7164250214540252
oct23155011237455
94605833518837
101320302231341
11469a3420a085
12193a72667351
13976722a1692
1447c8da65429
1524526491211
hex13368253f2d

1320302231341 has 2 divisors, whose sum is σ = 1320302231342. Its totient is φ = 1320302231340.

The previous prime is 1320302231249. The next prime is 1320302231383. The reversal of 1320302231341 is 1431322030231.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1290518720100 + 29783511241 = 1136010^2 + 172579^2 .

It is a cyclic number.

It is not a de Polignac number, because 1320302231341 - 211 = 1320302229293 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1320302231141) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 660151115670 + 660151115671.

It is an arithmetic number, because the mean of its divisors is an integer number (660151115671).

Almost surely, 21320302231341 is an apocalyptic number.

It is an amenable number.

1320302231341 is a deficient number, since it is larger than the sum of its proper divisors (1).

1320302231341 is an equidigital number, since it uses as much as digits as its factorization.

1320302231341 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 1320302231341 its reverse (1431322030231), we get a palindrome (2751624261572).

The spelling of 1320302231341 in words is "one trillion, three hundred twenty billion, three hundred two million, two hundred thirty-one thousand, three hundred forty-one".