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13203102210253 is a prime number
BaseRepresentation
bin1100000000100001011000…
…1101111001100011001101
31201202012111220010211012221
43000020112031321203031
53212304423131212003
644025231005455341
72531615116040224
oct300102615714315
951665456124187
1013203102210253
114230449aa241a
121592a24271551
1374a07c8c7657
14339068117cbb
1517d69a13e7bd
hexc02163798cd

13203102210253 has 2 divisors, whose sum is σ = 13203102210254. Its totient is φ = 13203102210252.

The previous prime is 13203102210229. The next prime is 13203102210313. The reversal of 13203102210253 is 35201220130231.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9604030327369 + 3599071882884 = 3099037^2 + 1897122^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13203102210253 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13203102210203) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6601551105126 + 6601551105127.

It is an arithmetic number, because the mean of its divisors is an integer number (6601551105127).

Almost surely, 213203102210253 is an apocalyptic number.

It is an amenable number.

13203102210253 is a deficient number, since it is larger than the sum of its proper divisors (1).

13203102210253 is an equidigital number, since it uses as much as digits as its factorization.

13203102210253 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2160, while the sum is 25.

Adding to 13203102210253 its reverse (35201220130231), we get a palindrome (48404322340484).

The spelling of 13203102210253 in words is "thirteen trillion, two hundred three billion, one hundred two million, two hundred ten thousand, two hundred fifty-three".