Base | Representation |
---|---|
bin | 10011001101101000101… |
… | …011001011100101100101 |
3 | 11200012221202021202011002 |
4 | 103031220223023211211 |
5 | 133112444121004424 |
6 | 2450313105123045 |
7 | 164250353156444 |
oct | 23155053134545 |
9 | 4605852252132 |
10 | 1320311109989 |
11 | 469a39223803 |
12 | 193a75629485 |
13 | 9767408ca11 |
14 | 47c90cd6d5b |
15 | 24527146cae |
hex | 13368acb965 |
1320311109989 has 2 divisors, whose sum is σ = 1320311109990. Its totient is φ = 1320311109988.
The previous prime is 1320311109947. The next prime is 1320311110007. The reversal of 1320311109989 is 9899011130231.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1318156572100 + 2154537889 = 1148110^2 + 46417^2 .
It is a cyclic number.
It is not a de Polignac number, because 1320311109989 - 240 = 220799482213 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1320311109589) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 660155554994 + 660155554995.
It is an arithmetic number, because the mean of its divisors is an integer number (660155554995).
Almost surely, 21320311109989 is an apocalyptic number.
It is an amenable number.
1320311109989 is a deficient number, since it is larger than the sum of its proper divisors (1).
1320311109989 is an equidigital number, since it uses as much as digits as its factorization.
1320311109989 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 104976, while the sum is 47.
The spelling of 1320311109989 in words is "one trillion, three hundred twenty billion, three hundred eleven million, one hundred nine thousand, nine hundred eighty-nine".
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