132032010113221 has 2 divisors, whose sum is σ = 132032010113222. Its totient is φ = 132032010113220.

The previous prime is 132032010113209. The next prime is 132032010113233. The reversal of 132032010113221 is 122311010230231.

It is a balanced prime because it is at equal distance from previous prime (132032010113209) and next prime (132032010113233).

It can be written as a sum of positive squares in only one way, i.e., 94511178682596 + 37520831430625 = 9721686^2 + 6125425^2 .

It is an emirp because it is prime and its reverse (122311010230231) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 132032010113221 - 2⁵ = 132032010113189 is a prime.

It is a super-3 number, since 3×132032010113221³ (a number of 43 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 132032010113192 and 132032010113201.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (132032010113921) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66016005056610 + 66016005056611.

It is an arithmetic number, because the mean of its divisors is an integer number (66016005056611).

Almost surely, 2^{132032010113221} is an apocalyptic number.

It is an amenable number.

132032010113221 is a deficient number, since it is larger than the sum of its proper divisors (1).

132032010113221 is an equidigital number, since it uses as much as digits as its factorization.

132032010113221 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 432, while the sum is 22.

Adding to 132032010113221 its reverse (122311010230231), we get a palindrome (254343020343452).

The spelling of 132032010113221 in words is "one hundred thirty-two trillion, thirty-two billion, ten million, one hundred thirteen thousand, two hundred twenty-one".