132032025540119 has 2 divisors, whose sum is σ = 132032025540120. Its totient is φ = 132032025540118.

The previous prime is 132032025540091. The next prime is 132032025540127. The reversal of 132032025540119 is 911045520230231.

It is a strong prime.

It is an emirp because it is prime and its reverse (911045520230231) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-132032025540119 is a prime.

It is a super-2 number, since 2×132032025540119² (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (132032025540719) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66016012770059 + 66016012770060.

It is an arithmetic number, because the mean of its divisors is an integer number (66016012770060).

Almost surely, 2^{132032025540119} is an apocalyptic number.

132032025540119 is a deficient number, since it is larger than the sum of its proper divisors (1).

132032025540119 is an equidigital number, since it uses as much as digits as its factorization.

132032025540119 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 64800, while the sum is 38.

The spelling of 132032025540119 in words is "one hundred thirty-two trillion, thirty-two billion, twenty-five million, five hundred forty thousand, one hundred nineteen".