Base | Representation |
---|---|
bin | 11110000001010100011010… |
… | …010000000001011111000110 |
3 | 122022111010202012001111010212 |
4 | 132001110122100001133012 |
5 | 114301203044143214332 |
6 | 1144450402142115422 |
7 | 36544666534163255 |
oct | 3601243220013706 |
9 | 568433665044125 |
10 | 132032030054342 |
11 | 39084518996a00 |
12 | 1298483787bb72 |
13 | 588974a94c622 |
14 | 248655493679c |
15 | 103e6c94ec8b2 |
hex | 78151a4017c6 |
132032030054342 has 24 divisors (see below), whose sum is σ = 218891876208096. Its totient is φ = 59682986946000.
The previous prime is 132032030054341. The next prime is 132032030054387. The reversal of 132032030054342 is 243450030230231.
It is a junction number, because it is equal to n+sod(n) for n = 132032030054299 and 132032030054308.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (132032030054341) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 1507102334 + ... + 1507189937.
It is an arithmetic number, because the mean of its divisors is an integer number (9120494842004).
Almost surely, 2132032030054342 is an apocalyptic number.
132032030054342 is a deficient number, since it is larger than the sum of its proper divisors (86859846153754).
132032030054342 is a wasteful number, since it uses less digits than its factorization.
132032030054342 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3014292476 (or 3014292465 counting only the distinct ones).
The product of its (nonzero) digits is 51840, while the sum is 32.
Adding to 132032030054342 its reverse (243450030230231), we get a palindrome (375482060284573).
The spelling of 132032030054342 in words is "one hundred thirty-two trillion, thirty-two billion, thirty million, fifty-four thousand, three hundred forty-two".
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