Base | Representation |
---|---|
bin | 1100000000100001110010… |
… | …1100111100010001100101 |
3 | 1201202012210110212111000122 |
4 | 3000020130230330101211 |
5 | 3212310134004324143 |
6 | 44025245453451325 |
7 | 2531620606606121 |
oct | 300103454742145 |
9 | 51665713774018 |
10 | 13203211011173 |
11 | 42304a5455137 |
12 | 1592a547a0b45 |
13 | 74a0992cccb1 |
14 | 33907875a581 |
15 | 17d6a4981c68 |
hex | c021cb3c465 |
13203211011173 has 2 divisors, whose sum is σ = 13203211011174. Its totient is φ = 13203211011172.
The previous prime is 13203211011061. The next prime is 13203211011217. The reversal of 13203211011173 is 37111011230231.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 13016170330849 + 187040680324 = 3607793^2 + 432482^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13203211011173 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13203211017173) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6601605505586 + 6601605505587.
It is an arithmetic number, because the mean of its divisors is an integer number (6601605505587).
Almost surely, 213203211011173 is an apocalyptic number.
It is an amenable number.
13203211011173 is a deficient number, since it is larger than the sum of its proper divisors (1).
13203211011173 is an equidigital number, since it uses as much as digits as its factorization.
13203211011173 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 756, while the sum is 26.
The spelling of 13203211011173 in words is "thirteen trillion, two hundred three billion, two hundred eleven million, eleven thousand, one hundred seventy-three".
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