13203211011217 has 2 divisors, whose sum is σ = 13203211011218. Its totient is φ = 13203211011216.

The previous prime is 13203211011173. The next prime is 13203211011241. The reversal of 13203211011217 is 71211011230231.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11918817188496 + 1284393822721 = 3452364^2 + 1133311^2 .

It is a cyclic number.

It is not a de Polignac number, because 13203211011217 - 2²³ = 13203202622609 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13203211011191 and 13203211011200.

It is not a weakly prime, because it can be changed into another prime (13203211011257) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6601605505608 + 6601605505609.

It is an arithmetic number, because the mean of its divisors is an integer number (6601605505609).

Almost surely, 2^{13203211011217} is an apocalyptic number.

It is an amenable number.

13203211011217 is a deficient number, since it is larger than the sum of its proper divisors (1).

13203211011217 is an equidigital number, since it uses as much as digits as its factorization.

13203211011217 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 504, while the sum is 25.

Adding to 13203211011217 its reverse (71211011230231), we get a palindrome (84414222241448).

The spelling of 13203211011217 in words is "thirteen trillion, two hundred three billion, two hundred eleven million, eleven thousand, two hundred seventeen".