Base | Representation |
---|---|
bin | 111101011110111001… |
… | …0101110011100100111 |
3 | 110121210121210000121111 |
4 | 1322331302232130213 |
5 | 4130401000211101 |
6 | 140353305525451 |
7 | 12352622524513 |
oct | 1727562563447 |
9 | 417717700544 |
10 | 132033210151 |
11 | 50aa4339aa7 |
12 | 217097a3887 |
13 | c5b21a906b |
14 | 656752b143 |
15 | 367b5d6251 |
hex | 1ebdcae727 |
132033210151 has 2 divisors, whose sum is σ = 132033210152. Its totient is φ = 132033210150.
The previous prime is 132033210149. The next prime is 132033210163. The reversal of 132033210151 is 151012330231.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 132033210151 - 21 = 132033210149 is a prime.
Together with 132033210149, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (132033219151) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66016605075 + 66016605076.
It is an arithmetic number, because the mean of its divisors is an integer number (66016605076).
Almost surely, 2132033210151 is an apocalyptic number.
132033210151 is a deficient number, since it is larger than the sum of its proper divisors (1).
132033210151 is an equidigital number, since it uses as much as digits as its factorization.
132033210151 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 540, while the sum is 22.
Adding to 132033210151 its reverse (151012330231), we get a palindrome (283045540382).
The spelling of 132033210151 in words is "one hundred thirty-two billion, thirty-three million, two hundred ten thousand, one hundred fifty-one".
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