Base | Representation |
---|---|
bin | 11000100101111101… |
… | …01101010001010100 |
3 | 1021002011101122222010 |
4 | 30102332231101110 |
5 | 204020023031012 |
6 | 10022053104220 |
7 | 645122311566 |
oct | 142276552124 |
9 | 37064348863 |
10 | 13203330132 |
11 | 5665a32393 |
12 | 2685928070 |
13 | 13255539a5 |
14 | 8d3777336 |
15 | 524217c3c |
hex | 312fad454 |
13203330132 has 12 divisors (see below), whose sum is σ = 30807770336. Its totient is φ = 4401110040.
The previous prime is 13203330103. The next prime is 13203330137. The reversal of 13203330132 is 23103330231.
13203330132 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a tau number, because it is divible by the number of its divisors (12).
It is a junction number, because it is equal to n+sod(n) for n = 13203330099 and 13203330108.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13203330137) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 550138744 + ... + 550138767.
Almost surely, 213203330132 is an apocalyptic number.
13203330132 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
13203330132 is an abundant number, since it is smaller than the sum of its proper divisors (17604440204).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13203330132 is a wasteful number, since it uses less digits than its factorization.
13203330132 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1100277518 (or 1100277516 counting only the distinct ones).
The product of its (nonzero) digits is 972, while the sum is 21.
Adding to 13203330132 its reverse (23103330231), we get a palindrome (36306660363).
Subtracting 13203330132 from its reverse (23103330231), we obtain a palindrome (9900000099).
It can be divided in two parts, 132033 and 30132, that added together give a triangular number (162165 = T569).
The spelling of 13203330132 in words is "thirteen billion, two hundred three million, three hundred thirty thousand, one hundred thirty-two".
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