Base | Representation |
---|---|
bin | 111101011110111001… |
… | …1000111100101100111 |
3 | 110121210121222020212102 |
4 | 1322331303013211213 |
5 | 4130401012010002 |
6 | 140353312042315 |
7 | 12352623433652 |
oct | 1727563074547 |
9 | 417717866772 |
10 | 132033313127 |
11 | 50aa43aa401 |
12 | 2170983339b |
13 | c5b2213bb1 |
14 | 6567556899 |
15 | 367b606a02 |
hex | 1ebdcc7967 |
132033313127 has 2 divisors, whose sum is σ = 132033313128. Its totient is φ = 132033313126.
The previous prime is 132033313121. The next prime is 132033313129. The reversal of 132033313127 is 721313330231.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 132033313127 - 26 = 132033313063 is a prime.
Together with 132033313129, it forms a pair of twin primes.
It is a Chen prime.
It is a self number, because there is not a number n which added to its sum of digits gives 132033313127.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (132033313121) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66016656563 + 66016656564.
It is an arithmetic number, because the mean of its divisors is an integer number (66016656564).
Almost surely, 2132033313127 is an apocalyptic number.
132033313127 is a deficient number, since it is larger than the sum of its proper divisors (1).
132033313127 is an equidigital number, since it uses as much as digits as its factorization.
132033313127 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6804, while the sum is 29.
Adding to 132033313127 its reverse (721313330231), we get a palindrome (853346643358).
The spelling of 132033313127 in words is "one hundred thirty-two billion, thirty-three million, three hundred thirteen thousand, one hundred twenty-seven".
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