Base | Representation |
---|---|
bin | 11110000001100001000000… |
… | …010010011001000011001111 |
3 | 122022112102122122001221210022 |
4 | 132001201000102121003033 |
5 | 114301413243044024442 |
6 | 1144500520100132355 |
7 | 36545655621235166 |
oct | 3601410022310317 |
9 | 568472578057708 |
10 | 132045553111247 |
11 | 3908a228346796 |
12 | 129873906970bb |
13 | 588aac44ba049 |
14 | 248707893a3dd |
15 | 103ec1b81e3d2 |
hex | 7818404990cf |
132045553111247 has 2 divisors, whose sum is σ = 132045553111248. Its totient is φ = 132045553111246.
The previous prime is 132045553111231. The next prime is 132045553111309. The reversal of 132045553111247 is 742111355540231.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 132045553111247 - 24 = 132045553111231 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 132045553111198 and 132045553111207.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (132045553113247) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66022776555623 + 66022776555624.
It is an arithmetic number, because the mean of its divisors is an integer number (66022776555624).
Almost surely, 2132045553111247 is an apocalyptic number.
132045553111247 is a deficient number, since it is larger than the sum of its proper divisors (1).
132045553111247 is an equidigital number, since it uses as much as digits as its factorization.
132045553111247 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 504000, while the sum is 44.
The spelling of 132045553111247 in words is "one hundred thirty-two trillion, forty-five billion, five hundred fifty-three million, one hundred eleven thousand, two hundred forty-seven".
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