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132045553111309 is a prime number
BaseRepresentation
bin11110000001100001000000…
…010010011001000100001101
3122022112102122122001221212121
4132001201000102121010031
5114301413243044030214
61144500520100132541
736545655621235315
oct3601410022310415
9568472578057777
10132045553111309
113908a228346842
1212987390697151
13588aac44ba096
14248707893a445
15103ec1b81e424
hex78184049910d

132045553111309 has 2 divisors, whose sum is σ = 132045553111310. Its totient is φ = 132045553111308.

The previous prime is 132045553111247. The next prime is 132045553111319. The reversal of 132045553111309 is 903111355540231.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 91030776410025 + 41014776701284 = 9541005^2 + 6404278^2 .

It is a cyclic number.

It is not a de Polignac number, because 132045553111309 - 213 = 132045553103117 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (132045553111319) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66022776555654 + 66022776555655.

It is an arithmetic number, because the mean of its divisors is an integer number (66022776555655).

Almost surely, 2132045553111309 is an apocalyptic number.

It is an amenable number.

132045553111309 is a deficient number, since it is larger than the sum of its proper divisors (1).

132045553111309 is an equidigital number, since it uses as much as digits as its factorization.

132045553111309 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 243000, while the sum is 43.

The spelling of 132045553111309 in words is "one hundred thirty-two trillion, forty-five billion, five hundred fifty-three million, one hundred eleven thousand, three hundred nine".