Base | Representation |
---|---|
bin | 11110000001100001000000… |
… | …010010011001000100001101 |
3 | 122022112102122122001221212121 |
4 | 132001201000102121010031 |
5 | 114301413243044030214 |
6 | 1144500520100132541 |
7 | 36545655621235315 |
oct | 3601410022310415 |
9 | 568472578057777 |
10 | 132045553111309 |
11 | 3908a228346842 |
12 | 12987390697151 |
13 | 588aac44ba096 |
14 | 248707893a445 |
15 | 103ec1b81e424 |
hex | 78184049910d |
132045553111309 has 2 divisors, whose sum is σ = 132045553111310. Its totient is φ = 132045553111308.
The previous prime is 132045553111247. The next prime is 132045553111319. The reversal of 132045553111309 is 903111355540231.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 91030776410025 + 41014776701284 = 9541005^2 + 6404278^2 .
It is a cyclic number.
It is not a de Polignac number, because 132045553111309 - 213 = 132045553103117 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (132045553111319) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66022776555654 + 66022776555655.
It is an arithmetic number, because the mean of its divisors is an integer number (66022776555655).
Almost surely, 2132045553111309 is an apocalyptic number.
It is an amenable number.
132045553111309 is a deficient number, since it is larger than the sum of its proper divisors (1).
132045553111309 is an equidigital number, since it uses as much as digits as its factorization.
132045553111309 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 243000, while the sum is 43.
The spelling of 132045553111309 in words is "one hundred thirty-two trillion, forty-five billion, five hundred fifty-three million, one hundred eleven thousand, three hundred nine".
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