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132052441510103 is a prime number
BaseRepresentation
bin11110000001100111011010…
…110111100011000011010111
3122022120002102200210212120212
4132001213122313203003113
5114302021400011310403
61144504015410320035
736546321413533532
oct3601473267430327
9568502380725525
10132052441510103
11390921426a5804
121298879358901b
13588b651649bba
14248752d725a19
15103eec14414d8
hex7819dade30d7

132052441510103 has 2 divisors, whose sum is σ = 132052441510104. Its totient is φ = 132052441510102.

The previous prime is 132052441510061. The next prime is 132052441510261. The reversal of 132052441510103 is 301015144250231.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 132052441510103 - 226 = 132052374401239 is a prime.

It is a Sophie Germain prime.

It is a self number, because there is not a number n which added to its sum of digits gives 132052441510103.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (132052441510303) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66026220755051 + 66026220755052.

It is an arithmetic number, because the mean of its divisors is an integer number (66026220755052).

Almost surely, 2132052441510103 is an apocalyptic number.

132052441510103 is a deficient number, since it is larger than the sum of its proper divisors (1).

132052441510103 is an equidigital number, since it uses as much as digits as its factorization.

132052441510103 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 14400, while the sum is 32.

Adding to 132052441510103 its reverse (301015144250231), we get a palindrome (433067585760334).

The spelling of 132052441510103 in words is "one hundred thirty-two trillion, fifty-two billion, four hundred forty-one million, five hundred ten thousand, one hundred three".