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132052544345221 is a prime number
BaseRepresentation
bin11110000001100111100000…
…111111110101010010000101
3122022120002200212022102211221
4132001213200333311102011
5114302022102323021341
61144504033522400341
736546324102604423
oct3601474077652205
9568502625272757
10132052544345221
1139092195753305
1212988801b000b1
13588b669a43c96
14248753d254113
15103eeca4a5ed1
hex7819e0ff5485

132052544345221 has 2 divisors, whose sum is σ = 132052544345222. Its totient is φ = 132052544345220.

The previous prime is 132052544345219. The next prime is 132052544345251. The reversal of 132052544345221 is 122543445250231.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 68813246390625 + 63239297954596 = 8295375^2 + 7952314^2 .

It is a cyclic number.

It is not a de Polignac number, because 132052544345221 - 21 = 132052544345219 is a prime.

Together with 132052544345219, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (132052544345251) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66026272172610 + 66026272172611.

It is an arithmetic number, because the mean of its divisors is an integer number (66026272172611).

Almost surely, 2132052544345221 is an apocalyptic number.

It is an amenable number.

132052544345221 is a deficient number, since it is larger than the sum of its proper divisors (1).

132052544345221 is an equidigital number, since it uses as much as digits as its factorization.

132052544345221 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1152000, while the sum is 43.

Adding to 132052544345221 its reverse (122543445250231), we get a palindrome (254595989595452).

The spelling of 132052544345221 in words is "one hundred thirty-two trillion, fifty-two billion, five hundred forty-four million, three hundred forty-five thousand, two hundred twenty-one".