Base | Representation |
---|---|
bin | 10011001101110111001… |
… | …110000101011110110000 |
3 | 11200020120202110210211011 |
4 | 103031313032011132300 |
5 | 133113444104003130 |
6 | 2450353223400304 |
7 | 164256405331312 |
oct | 23156716053660 |
9 | 4606522423734 |
10 | 1320555141040 |
11 | 46a053a4a963 |
12 | 193b232b3094 |
13 | 976b27c25a5 |
14 | 47cb549b7b2 |
15 | 2453d79c52a |
hex | 133773857b0 |
1320555141040 has 80 divisors (see below), whose sum is σ = 3232106748000. Its totient is φ = 500386553856.
The previous prime is 1320555140921. The next prime is 1320555141041. The reversal of 1320555141040 is 401415550231.
It is a tau number, because it is divible by the number of its divisors (80).
It is a junction number, because it is equal to n+sod(n) for n = 1320555140993 and 1320555141011.
It is not an unprimeable number, because it can be changed into a prime (1320555141041) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 38513344 + ... + 38547616.
It is an arithmetic number, because the mean of its divisors is an integer number (40401334350).
Almost surely, 21320555141040 is an apocalyptic number.
1320555141040 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
1320555141040 is an abundant number, since it is smaller than the sum of its proper divisors (1911551606960).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1320555141040 is a wasteful number, since it uses less digits than its factorization.
1320555141040 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 59654 (or 59648 counting only the distinct ones).
The product of its (nonzero) digits is 12000, while the sum is 31.
The spelling of 1320555141040 in words is "one trillion, three hundred twenty billion, five hundred fifty-five million, one hundred forty-one thousand, forty".
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