Base | Representation |
---|---|
bin | 11000100110010011… |
… | …10011101000000000 |
3 | 1021002100212111012112 |
4 | 30103021303220000 |
5 | 204021244132434 |
6 | 10022235314452 |
7 | 645156120455 |
oct | 142311635000 |
9 | 37070774175 |
10 | 13206239744 |
11 | 566763a425 |
12 | 26868aba28 |
13 | 1326032159 |
14 | 8d3cd382c |
15 | 5245dedce |
hex | 313273a00 |
13206239744 has 40 divisors (see below), whose sum is σ = 27938862468. Its totient is φ = 6214696960.
The previous prime is 13206239719. The next prime is 13206239773. The reversal of 13206239744 is 44793260231.
It can be written as a sum of positive squares in 2 ways, for example, as 12383238400 + 823001344 = 111280^2 + 28688^2 .
It is a super-4 number, since 4×132062397444 (a number of 42 digits) contains 4444 as substring.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 749927 + ... + 767334.
Almost surely, 213206239744 is an apocalyptic number.
It is an amenable number.
13206239744 is an abundant number, since it is smaller than the sum of its proper divisors (14732622724).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13206239744 is an equidigital number, since it uses as much as digits as its factorization.
13206239744 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1517296 (or 1517280 counting only the distinct ones).
The product of its (nonzero) digits is 217728, while the sum is 41.
Adding to 13206239744 its reverse (44793260231), we get a palindrome (57999499975).
The spelling of 13206239744 in words is "thirteen billion, two hundred six million, two hundred thirty-nine thousand, seven hundred forty-four".
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