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13207748471 is a prime number
BaseRepresentation
bin11000100110011111…
…00011111101110111
31021002110201010210022
430103033203331313
5204022140422341
610022331515355
7645205003211
oct142317437567
937073633708
1013207748471
11566847aa05
1226872b8b5b
13132643caa8
148d41a75b1
155247dbe4b
hex3133e3f77

13207748471 has 2 divisors, whose sum is σ = 13207748472. Its totient is φ = 13207748470.

The previous prime is 13207748399. The next prime is 13207748473. The reversal of 13207748471 is 17484770231.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 13207748471 - 226 = 13140639607 is a prime.

It is a super-3 number, since 3×132077484713 (a number of 31 digits) contains 333 as substring.

Together with 13207748473, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13207748473) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6603874235 + 6603874236.

It is an arithmetic number, because the mean of its divisors is an integer number (6603874236).

Almost surely, 213207748471 is an apocalyptic number.

13207748471 is a deficient number, since it is larger than the sum of its proper divisors (1).

13207748471 is an equidigital number, since it uses as much as digits as its factorization.

13207748471 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 263424, while the sum is 44.

The spelling of 13207748471 in words is "thirteen billion, two hundred seven million, seven hundred forty-eight thousand, four hundred seventy-one".