Base | Representation |
---|---|
bin | 11000100110011111… |
… | …00011111101110111 |
3 | 1021002110201010210022 |
4 | 30103033203331313 |
5 | 204022140422341 |
6 | 10022331515355 |
7 | 645205003211 |
oct | 142317437567 |
9 | 37073633708 |
10 | 13207748471 |
11 | 566847aa05 |
12 | 26872b8b5b |
13 | 132643caa8 |
14 | 8d41a75b1 |
15 | 5247dbe4b |
hex | 3133e3f77 |
13207748471 has 2 divisors, whose sum is σ = 13207748472. Its totient is φ = 13207748470.
The previous prime is 13207748399. The next prime is 13207748473. The reversal of 13207748471 is 17484770231.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13207748471 - 226 = 13140639607 is a prime.
It is a super-3 number, since 3×132077484713 (a number of 31 digits) contains 333 as substring.
Together with 13207748473, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13207748473) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6603874235 + 6603874236.
It is an arithmetic number, because the mean of its divisors is an integer number (6603874236).
Almost surely, 213207748471 is an apocalyptic number.
13207748471 is a deficient number, since it is larger than the sum of its proper divisors (1).
13207748471 is an equidigital number, since it uses as much as digits as its factorization.
13207748471 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 263424, while the sum is 44.
The spelling of 13207748471 in words is "thirteen billion, two hundred seven million, seven hundred forty-eight thousand, four hundred seventy-one".
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