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13208038250101 is a prime number
BaseRepresentation
bin1100000000110011110001…
…1011011001011001110101
31201202200020220011121221121
43000030330123121121311
53212400030243000401
644031404454143541
72532151333505032
oct300147433313165
951680226147847
1013208038250101
1142325522941a2
121593981351bb1
1374a6884208a6
143393b58ca389
1517d88865eca1
hexc033c6d9675

13208038250101 has 2 divisors, whose sum is σ = 13208038250102. Its totient is φ = 13208038250100.

The previous prime is 13208038250089. The next prime is 13208038250149. The reversal of 13208038250101 is 10105283080231.

13208038250101 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 8472605279076 + 4735432971025 = 2910774^2 + 2176105^2 .

It is a cyclic number.

It is not a de Polignac number, because 13208038250101 - 235 = 13173678511733 is a prime.

It is a super-2 number, since 2×132080382501012 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13208038250401) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6604019125050 + 6604019125051.

It is an arithmetic number, because the mean of its divisors is an integer number (6604019125051).

Almost surely, 213208038250101 is an apocalyptic number.

It is an amenable number.

13208038250101 is a deficient number, since it is larger than the sum of its proper divisors (1).

13208038250101 is an equidigital number, since it uses as much as digits as its factorization.

13208038250101 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 11520, while the sum is 34.

The spelling of 13208038250101 in words is "thirteen trillion, two hundred eight billion, thirty-eight million, two hundred fifty thousand, one hundred one".