Base | Representation |
---|---|
bin | 11000100110100101… |
… | …00011011110000111 |
3 | 1021002112011222210011 |
4 | 30103102203132013 |
5 | 204022341022441 |
6 | 10022400411051 |
7 | 645214451122 |
oct | 142322433607 |
9 | 37075158704 |
10 | 13208532871 |
11 | 5668966276 |
12 | 2687616a87 |
13 | 1326655b31 |
14 | 8d432d3b9 |
15 | 5248e4581 |
hex | 3134a3787 |
13208532871 has 2 divisors, whose sum is σ = 13208532872. Its totient is φ = 13208532870.
The previous prime is 13208532829. The next prime is 13208532923. The reversal of 13208532871 is 17823580231.
It is a happy number.
13208532871 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13208532871 - 211 = 13208530823 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13208532671) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6604266435 + 6604266436.
It is an arithmetic number, because the mean of its divisors is an integer number (6604266436).
Almost surely, 213208532871 is an apocalyptic number.
13208532871 is a deficient number, since it is larger than the sum of its proper divisors (1).
13208532871 is an equidigital number, since it uses as much as digits as its factorization.
13208532871 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 80640, while the sum is 40.
The spelling of 13208532871 in words is "thirteen billion, two hundred eight million, five hundred thirty-two thousand, eight hundred seventy-one".
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