Base | Representation |
---|---|
bin | 11110000010010011101110… |
… | …001011000001100100100111 |
3 | 122022201122012211100201020111 |
4 | 132002103232023001210213 |
5 | 114303311310031220312 |
6 | 1144541523512513451 |
7 | 36552624252322312 |
oct | 3602235613014447 |
9 | 568648184321214 |
10 | 132100010023207 |
11 | 391003328aa756 |
12 | 12995a4a0ab887 |
13 | 5892c92728285 |
14 | 248996315b979 |
15 | 10413575e08a7 |
hex | 7824ee2c1927 |
132100010023207 has 2 divisors, whose sum is σ = 132100010023208. Its totient is φ = 132100010023206.
The previous prime is 132100010023183. The next prime is 132100010023213. The reversal of 132100010023207 is 702320010001231.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 132100010023207 - 211 = 132100010021159 is a prime.
It is a super-3 number, since 3×1321000100232073 (a number of 43 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (132100010023307) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66050005011603 + 66050005011604.
It is an arithmetic number, because the mean of its divisors is an integer number (66050005011604).
Almost surely, 2132100010023207 is an apocalyptic number.
132100010023207 is a deficient number, since it is larger than the sum of its proper divisors (1).
132100010023207 is an equidigital number, since it uses as much as digits as its factorization.
132100010023207 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 504, while the sum is 22.
Adding to 132100010023207 its reverse (702320010001231), we get a palindrome (834420020024438).
The spelling of 132100010023207 in words is "one hundred thirty-two trillion, one hundred billion, ten million, twenty-three thousand, two hundred seven".
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