Base | Representation |
---|---|
bin | 11110000010010100000101… |
… | …011100010010010100010011 |
3 | 122022201200020000222010201221 |
4 | 132002110011130102110103 |
5 | 114303313110002033321 |
6 | 1144542030340305511 |
7 | 36552640032554542 |
oct | 3602240534222423 |
9 | 568650200863657 |
10 | 132100400424211 |
11 | 3910051320980a |
12 | 12995b389a2297 |
13 | 589302558869b |
14 | 248999cd44159 |
15 | 104137ba09e41 |
hex | 782505712513 |
132100400424211 has 2 divisors, whose sum is σ = 132100400424212. Its totient is φ = 132100400424210.
The previous prime is 132100400424163. The next prime is 132100400424259. The reversal of 132100400424211 is 112424004001231.
It is a balanced prime because it is at equal distance from previous prime (132100400424163) and next prime (132100400424259).
It is a cyclic number.
It is not a de Polignac number, because 132100400424211 - 29 = 132100400423699 is a prime.
It is not a weakly prime, because it can be changed into another prime (132100400424281) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66050200212105 + 66050200212106.
It is an arithmetic number, because the mean of its divisors is an integer number (66050200212106).
Almost surely, 2132100400424211 is an apocalyptic number.
132100400424211 is a deficient number, since it is larger than the sum of its proper divisors (1).
132100400424211 is an equidigital number, since it uses as much as digits as its factorization.
132100400424211 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1536, while the sum is 25.
Adding to 132100400424211 its reverse (112424004001231), we get a palindrome (244524404425442).
The spelling of 132100400424211 in words is "one hundred thirty-two trillion, one hundred billion, four hundred million, four hundred twenty-four thousand, two hundred eleven".
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