1321040112 has 40 divisors (see below), whose sum is σ = 3900214656. Its totient is φ = 377439936.

The previous prime is 1321040111. The next prime is 1321040137. The reversal of 1321040112 is 2110401231.

It is a junction number, because it is equal to n+sod(n) for n = 1321040091 and 1321040100.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1321040111) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1965498 + ... + 1966169.

Almost surely, 2^1321040112 is an apocalyptic number.

1321040112 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

1321040112 is an abundant number, since it is smaller than the sum of its proper divisors (2579174544).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1321040112 is a wasteful number, since it uses less digits than its factorization.

1321040112 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3931685 (or 3931679 counting only the distinct ones).

The product of its (nonzero) digits is 48, while the sum is 15.

The square root of 1321040112 is about 36346.1155008345. The cubic root of 1321040112 is about 1097.2493567175.

Adding to 1321040112 its reverse (2110401231), we get a palindrome (3431441343).

The spelling of 1321040112 in words is "one billion, three hundred twenty-one million, forty thousand, one hundred twelve".