Base | Representation |
---|---|
bin | 111101100001000001… |
… | …0010101010100100000 |
3 | 110121222120202100222202 |
4 | 1323002002111110200 |
5 | 4131022212113100 |
6 | 140404331552332 |
7 | 12354445650434 |
oct | 1730202252440 |
9 | 417876670882 |
10 | 132104410400 |
11 | 5103054a886 |
12 | 217295bb6a8 |
13 | c5c3b77ca1 |
14 | 6572b829c4 |
15 | 368299c7d5 |
hex | 1ec2095520 |
132104410400 has 36 divisors (see below), whose sum is σ = 322499893842. Its totient is φ = 52841763840.
The previous prime is 132104410343. The next prime is 132104410411. The reversal of 132104410400 is 4014401231.
It can be written as a sum of positive squares in 3 ways, for example, as 65501188624 + 66603221776 = 255932^2 + 258076^2 .
It is a Harshad number since it is a multiple of its sum of digits (20).
It is an unprimeable number.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 82564457 + ... + 82566056.
Almost surely, 2132104410400 is an apocalyptic number.
132104410400 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
132104410400 is an abundant number, since it is smaller than the sum of its proper divisors (190395483442).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
132104410400 is a wasteful number, since it uses less digits than its factorization.
132104410400 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 165130533 (or 165130520 counting only the distinct ones).
The product of its (nonzero) digits is 384, while the sum is 20.
Adding to 132104410400 its reverse (4014401231), we get a palindrome (136118811631).
The spelling of 132104410400 in words is "one hundred thirty-two billion, one hundred four million, four hundred ten thousand, four hundred".
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