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132104422134143 = 199663841317257
BaseRepresentation
bin11110000010010111110101…
…001001111001000101111111
3122022202001121022112011121122
4132002113311021321011333
5114303344324031243033
61144543533403421155
736553141505541434
oct3602276511710577
9568661538464548
10132104422134143
1139102197380a28
121299687b8247bb
13589351683b8c4
142489c61109b8b
151041514b1ca98
hex7825f527917f

132104422134143 has 4 divisors (see below), whose sum is σ = 132768263451600. Its totient is φ = 131440580816688.

The previous prime is 132104422134121. The next prime is 132104422134173. The reversal of 132104422134143 is 341431224401231.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 132104422134143 - 216 = 132104422068607 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (132104422134173) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 331920658430 + ... + 331920658827.

It is an arithmetic number, because the mean of its divisors is an integer number (33192065862900).

Almost surely, 2132104422134143 is an apocalyptic number.

132104422134143 is a deficient number, since it is larger than the sum of its proper divisors (663841317457).

132104422134143 is an equidigital number, since it uses as much as digits as its factorization.

132104422134143 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 663841317456.

The product of its (nonzero) digits is 55296, while the sum is 35.

Adding to 132104422134143 its reverse (341431224401231), we get a palindrome (473535646535374).

The spelling of 132104422134143 in words is "one hundred thirty-two trillion, one hundred four billion, four hundred twenty-two million, one hundred thirty-four thousand, one hundred forty-three".

Divisors: 1 199 663841317257 132104422134143