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132104422134173 is a prime number
BaseRepresentation
bin11110000010010111110101…
…001001111001000110011101
3122022202001121022112011122202
4132002113311021321012131
5114303344324031243143
61144543533403421245
736553141505541506
oct3602276511710635
9568661538464582
10132104422134173
1139102197380a55
121299687b824825
13589351683b918
142489c61109bad
151041514b1cab8
hex7825f527919d

132104422134173 has 2 divisors, whose sum is σ = 132104422134174. Its totient is φ = 132104422134172.

The previous prime is 132104422134121. The next prime is 132104422134227. The reversal of 132104422134173 is 371431224401231.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 129558619993924 + 2545802140249 = 11382382^2 + 1595557^2 .

It is an emirp because it is prime and its reverse (371431224401231) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 132104422134173 - 222 = 132104417939869 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (132104422130173) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66052211067086 + 66052211067087.

It is an arithmetic number, because the mean of its divisors is an integer number (66052211067087).

Almost surely, 2132104422134173 is an apocalyptic number.

It is an amenable number.

132104422134173 is a deficient number, since it is larger than the sum of its proper divisors (1).

132104422134173 is an equidigital number, since it uses as much as digits as its factorization.

132104422134173 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 96768, while the sum is 38.

The spelling of 132104422134173 in words is "one hundred thirty-two trillion, one hundred four billion, four hundred twenty-two million, one hundred thirty-four thousand, one hundred seventy-three".