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132104422134142 = 2473845113939621
BaseRepresentation
bin11110000010010111110101…
…001001111001000101111110
3122022202001121022112011121121
4132002113311021321011332
5114303344324031243032
61144543533403421154
736553141505541433
oct3602276511710576
9568661538464547
10132104422134142
1139102197380a27
121299687b8247ba
13589351683b8c3
142489c61109b8a
151041514b1ca97
hex7825f527917e

132104422134142 has 8 divisors (see below), whose sum is σ = 198156689235432. Its totient is φ = 66052192389000.

The previous prime is 132104422134121. The next prime is 132104422134173. The reversal of 132104422134142 is 241431224401231.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a junction number, because it is equal to n+sod(n) for n = 132104422134098 and 132104422134107.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2507092 + ... + 16446712.

It is an arithmetic number, because the mean of its divisors is an integer number (24769586154429).

Almost surely, 2132104422134142 is an apocalyptic number.

132104422134142 is a deficient number, since it is larger than the sum of its proper divisors (66052267101290).

132104422134142 is a wasteful number, since it uses less digits than its factorization.

132104422134142 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 18678074.

The product of its (nonzero) digits is 36864, while the sum is 34.

Adding to 132104422134142 its reverse (241431224401231), we get a palindrome (373535646535373).

The spelling of 132104422134142 in words is "one hundred thirty-two trillion, one hundred four billion, four hundred twenty-two million, one hundred thirty-four thousand, one hundred forty-two".

Divisors: 1 2 4738451 9476902 13939621 27879242 66052211067071 132104422134142