Base | Representation |
---|---|
bin | 1100000000111110110100… |
… | …0010101111001110111101 |
3 | 1201202221220101202212011221 |
4 | 3000033231002233032331 |
5 | 3212422112321300044 |
6 | 44033014503513341 |
7 | 2532314633455315 |
oct | 300175502571675 |
9 | 51687811685157 |
10 | 13211001353149 |
11 | 4233832943396 |
12 | 1594469758851 |
13 | 74aa3b286ac2 |
14 | 3395b724a445 |
15 | 17d9ad866484 |
hex | c03ed0af3bd |
13211001353149 has 2 divisors, whose sum is σ = 13211001353150. Its totient is φ = 13211001353148.
The previous prime is 13211001352807. The next prime is 13211001353177. The reversal of 13211001353149 is 94135310011231.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 12662972069049 + 548029284100 = 3558507^2 + 740290^2 .
It is a cyclic number.
It is not a de Polignac number, because 13211001353149 - 233 = 13202411418557 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13211001354149) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6605500676574 + 6605500676575.
It is an arithmetic number, because the mean of its divisors is an integer number (6605500676575).
Almost surely, 213211001353149 is an apocalyptic number.
It is an amenable number.
13211001353149 is a deficient number, since it is larger than the sum of its proper divisors (1).
13211001353149 is an equidigital number, since it uses as much as digits as its factorization.
13211001353149 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 9720, while the sum is 34.
The spelling of 13211001353149 in words is "thirteen trillion, two hundred eleven billion, one million, three hundred fifty-three thousand, one hundred forty-nine".
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