132112341042440 has 64 divisors (see below), whose sum is σ = 325921816186560. Its totient is φ = 47796989067520.

The previous prime is 132112341042433. The next prime is 132112341042469. The reversal of 132112341042440 is 44240143211231.

It is a junction number, because it is equal to n+sod(n) for n = 132112341042397 and 132112341042406.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 761982662 + ... + 762156021.

It is an arithmetic number, because the mean of its divisors is an integer number (5092528377915).

Almost surely, 2^{132112341042440} is an apocalyptic number.

132112341042440 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

132112341042440 is an abundant number, since it is smaller than the sum of its proper divisors (193809475144120).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

132112341042440 is a wasteful number, since it uses less digits than its factorization.

132112341042440 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1524138902 (or 1524138898 counting only the distinct ones).

The product of its (nonzero) digits is 18432, while the sum is 32.

Adding to 132112341042440 its reverse (44240143211231), we get a palindrome (176352484253671).

The spelling of 132112341042440 in words is "one hundred thirty-two trillion, one hundred twelve billion, three hundred forty-one million, forty-two thousand, four hundred forty".